What are the solutions to the equation x^2-20+12=0 ?

The solutions to the equation x^2-20+12=0 are x=2sqrt(2),x=-2sqrt(2)

Find the zeros of x^2-20+12=0

The zeros of x^2-20+12=0 are x=2sqrt(2),x=-2sqrt(2)

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x^{2} - 20 + 12 = 0

x = 22, x = - 22

Decimal Notation

x = 2.82842 \dots, x = - 2.82842 \dots

Solution steps

x^{2} - 20 + 12 = 0

Move

20

to the right side

x^{2} + 12 = 20

Move

12

to the right side

x^{2} = 8

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 8, x = - 8

8 = 22

- 8 = - 22

x = 22, x = - 22

0 = 3 x (x - 1) - (3 x + 7)

10 x^{2} + 5 = 1

25 = x^{2} + 14 x + 49

2 x^{2} - 3 x = - 2

115 + 12.25 t - 4.9 t^{2}

What are the solutions to the equation x^2-20+12=0 ?
The solutions to the equation x^2-20+12=0 are x=2sqrt(2),x=-2sqrt(2)
Find the zeros of x^2-20+12=0
The zeros of x^2-20+12=0 are x=2sqrt(2),x=-2sqrt(2)