What are the solutions to the equation 5x^2+7=27 ?

The solutions to the equation 5x^2+7=27 are x=2,x=-2

Find the zeros of 5x^2+7=27

The zeros of 5x^2+7=27 are x=2,x=-2

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5 x^{2} + 7 = 27

x = 2, x = - 2

Solution steps

5 x^{2} + 7 = 27

Move

7

to the right side

5 x^{2} = 20

Divide both sides by

5

x^{2} = 4

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 4, x = - 4

4 = 2

- 4 = - 2

x = 2, x = - 2

0 = - x^{2} + 5 x - 4

2 n^{2} + 15 n + 7 = 0

x^{2} + m x + 7 = 0, m > 0

3 x^{2} - x = - 2

2 y^{2} = 6 y

What are the solutions to the equation 5x^2+7=27 ?
The solutions to the equation 5x^2+7=27 are x=2,x=-2
Find the zeros of 5x^2+7=27
The zeros of 5x^2+7=27 are x=2,x=-2