What are the solutions to the equation x^2+4x-72=5x ?

The solutions to the equation x^2+4x-72=5x are x=9,x=-8

Find the zeros of x^2+4x-72=5x

The zeros of x^2+4x-72=5x are x=9,x=-8

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x^{2} + 4 x - 72 = 5 x

x = 9, x = - 8

Solution steps

x^{2} + 4 x - 72 = 5 x

Move

5 x

to the left side

x^{2} - x - 72 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 1 \cdot ( - 72 )}{2 \cdot 1}

(- 1)^{2} - 4 \cdot 1 \cdot (- 72) = 17

x_{1, 2} = \frac{- ( - 1 ) \pm 17}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 17}{2 \cdot 1}, x_{2} = \frac{- ( - 1 ) - 17}{2 \cdot 1}

x = \frac{- ( - 1 ) + 17}{2 \cdot 1} : 9

x = \frac{- ( - 1 ) - 17}{2 \cdot 1} : - 8

The solutions to the quadratic equation are:

x = 9, x = - 8

v^{2} + 8 v + 16 = 0

7 w^{2} = 448

x^{2} - 51 = 14 x

x^{2} + 20 x + 28 = 0

x (4 x + 7) = 2

What are the solutions to the equation x^2+4x-72=5x ?
The solutions to the equation x^2+4x-72=5x are x=9,x=-8
Find the zeros of x^2+4x-72=5x
The zeros of x^2+4x-72=5x are x=9,x=-8