What are the solutions to the equation 3x^2+10x-17=-9 ?

The solutions to the equation 3x^2+10x-17=-9 are x= 2/3 ,x=-4

Find the zeros of 3x^2+10x-17=-9

The zeros of 3x^2+10x-17=-9 are x= 2/3 ,x=-4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

3 x^{2} + 10 x - 17 = - 9

x = \frac{2}{3}, x = - 4

Solution steps

3 x^{2} + 10 x - 17 = - 9

Move

9

to the left side

3 x^{2} + 10 x - 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 3 ( - 8 )}{2 \cdot 3}

1 0^{2} - 4 \cdot 3 (- 8) = 14

x_{1, 2} = \frac{- 10 \pm 14}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 10 + 14}{2 \cdot 3}, x_{2} = \frac{- 10 - 14}{2 \cdot 3}

x = \frac{- 10 + 14}{2 \cdot 3} : \frac{2}{3}

x = \frac{- 10 - 14}{2 \cdot 3} : - 4

The solutions to the quadratic equation are:

x = \frac{2}{3}, x = - 4

x^{2} + 4 x - 72 = 5 x

v^{2} + 8 v + 16 = 0

7 w^{2} = 448

x^{2} - 51 = 14 x

x^{2} + 20 x + 28 = 0

What are the solutions to the equation 3x^2+10x-17=-9 ?
The solutions to the equation 3x^2+10x-17=-9 are x= 2/3 ,x=-4
Find the zeros of 3x^2+10x-17=-9
The zeros of 3x^2+10x-17=-9 are x= 2/3 ,x=-4