What are the solutions to the equation x^2+8x+2=22 ?

The solutions to the equation x^2+8x+2=22 are x=2,x=-10

Find the zeros of x^2+8x+2=22

The zeros of x^2+8x+2=22 are x=2,x=-10

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x^{2} + 8 x + 2 = 22

x = 2, x = - 10

Solution steps

x^{2} + 8 x + 2 = 22

Move

22

to the left side

x^{2} + 8 x - 20 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 1 \cdot ( - 20 )}{2 \cdot 1}

8^{2} - 4 \cdot 1 \cdot (- 20) = 12

x_{1, 2} = \frac{- 8 \pm 12}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 8 + 12}{2 \cdot 1}, x_{2} = \frac{- 8 - 12}{2 \cdot 1}

x = \frac{- 8 + 12}{2 \cdot 1} : 2

x = \frac{- 8 - 12}{2 \cdot 1} : - 10

The solutions to the quadratic equation are:

x = 2, x = - 10

8 m^{2} - 3 m + 6 = 0

5 y^{2} - 15 y = 0

- 21 x + 10 = - 10 x^{2}

2 x^{2} = 6 x - 4

y^{2} - 7 y - 18 = 0

What are the solutions to the equation x^2+8x+2=22 ?
The solutions to the equation x^2+8x+2=22 are x=2,x=-10
Find the zeros of x^2+8x+2=22
The zeros of x^2+8x+2=22 are x=2,x=-10