What are the solutions to the equation x^2=-20x ?

The solutions to the equation x^2=-20x are x=0,x=-20

Find the zeros of x^2=-20x

The zeros of x^2=-20x are x=0,x=-20

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x^{2} = - 20 x

x = 0, x = - 20

Solution steps

x^{2} = - 20 x

Move

20 x

to the left side

x^{2} + 20 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 20 \pm 2 0 ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

2 0^{2} - 4 \cdot 1 \cdot 0 = 20

x_{1, 2} = \frac{- 20 \pm 20}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 20 + 20}{2 \cdot 1}, x_{2} = \frac{- 20 - 20}{2 \cdot 1}

x = \frac{- 20 + 20}{2 \cdot 1} : 0

x = \frac{- 20 - 20}{2 \cdot 1} : - 20

The solutions to the quadratic equation are:

x = 0, x = - 20

4 x^{2} + 169 = 0

x^{2} + 8 x + 2 = 22

8 m^{2} - 3 m + 6 = 0

5 y^{2} - 15 y = 0

- 21 x + 10 = - 10 x^{2}

What are the solutions to the equation x^2=-20x ?
The solutions to the equation x^2=-20x are x=0,x=-20
Find the zeros of x^2=-20x
The zeros of x^2=-20x are x=0,x=-20