What are the solutions to the equation 8m^2-3m+6=0 ?

The solutions to the equation 8m^2-3m+6=0 are m= 3/16+i(sqrt(183))/(16),m= 3/16-i(sqrt(183))/(16)

Find the zeros of 8m^2-3m+6=0

The zeros of 8m^2-3m+6=0 are m= 3/16+i(sqrt(183))/(16),m= 3/16-i(sqrt(183))/(16)

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8 m^{2} - 3 m + 6 = 0

m = \frac{3}{16} + i \frac{183}{16}, m = \frac{3}{16} - i \frac{183}{16}

Solution steps

8 m^{2} - 3 m + 6 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 8 \cdot 6}{2 \cdot 8}

Simplify

(- 3)^{2} - 4 \cdot 8 \cdot 6 : 183 i

m_{1, 2} = \frac{- ( - 3 ) \pm 183 i}{2 \cdot 8}

Separate the solutions

m_{1} = \frac{- ( - 3 ) + 183 i}{2 \cdot 8}, m_{2} = \frac{- ( - 3 ) - 183 i}{2 \cdot 8}

m = \frac{- ( - 3 ) + 183 i}{2 \cdot 8} : \frac{3}{16} + i \frac{183}{16}

m = \frac{- ( - 3 ) - 183 i}{2 \cdot 8} : \frac{3}{16} - i \frac{183}{16}

The solutions to the quadratic equation are:

m = \frac{3}{16} + i \frac{183}{16}, m = \frac{3}{16} - i \frac{183}{16}

5 y^{2} - 15 y = 0

- 21 x + 10 = - 10 x^{2}

2 x^{2} = 6 x - 4

y^{2} - 7 y - 18 = 0

x^{2} + 18 x = - 76

What are the solutions to the equation 8m^2-3m+6=0 ?
The solutions to the equation 8m^2-3m+6=0 are m= 3/16+i(sqrt(183))/(16),m= 3/16-i(sqrt(183))/(16)
Find the zeros of 8m^2-3m+6=0
The zeros of 8m^2-3m+6=0 are m= 3/16+i(sqrt(183))/(16),m= 3/16-i(sqrt(183))/(16)