What are the solutions to the equation y^2-7y-18=0 ?

The solutions to the equation y^2-7y-18=0 are y=9,y=-2

Find the zeros of y^2-7y-18=0

The zeros of y^2-7y-18=0 are y=9,y=-2

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y^{2} - 7 y - 18 = 0

y = 9, y = - 2

Solution steps

y^{2} - 7 y - 18 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 1 \cdot ( - 18 )}{2 \cdot 1}

(- 7)^{2} - 4 \cdot 1 \cdot (- 18) = 11

y_{1, 2} = \frac{- ( - 7 ) \pm 11}{2 \cdot 1}

Separate the solutions

y_{1} = \frac{- ( - 7 ) + 11}{2 \cdot 1}, y_{2} = \frac{- ( - 7 ) - 11}{2 \cdot 1}

y = \frac{- ( - 7 ) + 11}{2 \cdot 1} : 9

y = \frac{- ( - 7 ) - 11}{2 \cdot 1} : - 2

The solutions to the quadratic equation are:

y = 9, y = - 2

x^{2} + 18 x = - 76

x, 6 x^{2} + 3 y^{2} - 12 x + 10 = 0

2 x^{2} + 3 x - 65 = 0

13 x^{2} - 6 x + 1 = 0

4 x^{2} + 160 = 0

What are the solutions to the equation y^2-7y-18=0 ?
The solutions to the equation y^2-7y-18=0 are y=9,y=-2
Find the zeros of y^2-7y-18=0
The zeros of y^2-7y-18=0 are y=9,y=-2