What are the solutions to the equation x^2+18x=-76 ?

The solutions to the equation x^2+18x=-76 are x=-9+sqrt(5),x=-9-sqrt(5)

Find the zeros of x^2+18x=-76

The zeros of x^2+18x=-76 are x=-9+sqrt(5),x=-9-sqrt(5)

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x^{2} + 18 x = - 76

x = - 9 + 5, x = - 9 - 5

Decimal Notation

x = - 6.76393 \dots, x = - 11.23606 \dots

Solution steps

x^{2} + 18 x = - 76

Move

76

to the left side

x^{2} + 18 x + 76 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 18 \pm 1 8 ^{2} - 4 \cdot 1 \cdot 76}{2 \cdot 1}

1 8^{2} - 4 \cdot 1 \cdot 76 = 25

x_{1, 2} = \frac{- 18 \pm 2 5}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 18 + 2 5}{2 \cdot 1}, x_{2} = \frac{- 18 - 2 5}{2 \cdot 1}

x = \frac{- 18 + 2 5}{2 \cdot 1} : - 9 + 5

x = \frac{- 18 - 2 5}{2 \cdot 1} : - 9 - 5

The solutions to the quadratic equation are:

x = - 9 + 5, x = - 9 - 5

x, 6 x^{2} + 3 y^{2} - 12 x + 10 = 0

2 x^{2} + 3 x - 65 = 0

13 x^{2} - 6 x + 1 = 0

4 x^{2} + 160 = 0

(3 y - 2)^{2} = 18

What are the solutions to the equation x^2+18x=-76 ?
The solutions to the equation x^2+18x=-76 are x=-9+sqrt(5),x=-9-sqrt(5)
Find the zeros of x^2+18x=-76
The zeros of x^2+18x=-76 are x=-9+sqrt(5),x=-9-sqrt(5)