What are the solutions to the equation 13x^2-6x+1=0 ?

The solutions to the equation 13x^2-6x+1=0 are x= 3/13+i 2/13 ,x= 3/13-i 2/13

Find the zeros of 13x^2-6x+1=0

The zeros of 13x^2-6x+1=0 are x= 3/13+i 2/13 ,x= 3/13-i 2/13

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13 x^{2} - 6 x + 1 = 0

x = \frac{3}{13} + i \frac{2}{13}, x = \frac{3}{13} - i \frac{2}{13}

Solution steps

13 x^{2} - 6 x + 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 13 \cdot 1}{2 \cdot 13}

Simplify

(- 6)^{2} - 4 \cdot 13 \cdot 1 : 4 i

x_{1, 2} = \frac{- ( - 6 ) \pm 4 i}{2 \cdot 13}

Separate the solutions

x_{1} = \frac{- ( - 6 ) + 4 i}{2 \cdot 13}, x_{2} = \frac{- ( - 6 ) - 4 i}{2 \cdot 13}

x = \frac{- ( - 6 ) + 4 i}{2 \cdot 13} : \frac{3}{13} + i \frac{2}{13}

x = \frac{- ( - 6 ) - 4 i}{2 \cdot 13} : \frac{3}{13} - i \frac{2}{13}

The solutions to the quadratic equation are:

x = \frac{3}{13} + i \frac{2}{13}, x = \frac{3}{13} - i \frac{2}{13}

4 x^{2} + 160 = 0

(3 y - 2)^{2} = 18

(x + 1) (x - 3) = 12

5 x^{2} - 4 x - 1 = 0

4 x (x - 3) = 0

What are the solutions to the equation 13x^2-6x+1=0 ?
The solutions to the equation 13x^2-6x+1=0 are x= 3/13+i 2/13 ,x= 3/13-i 2/13
Find the zeros of 13x^2-6x+1=0
The zeros of 13x^2-6x+1=0 are x= 3/13+i 2/13 ,x= 3/13-i 2/13