What are the solutions to the equation m^2+m-12=0 ?

The solutions to the equation m^2+m-12=0 are m=3,m=-4

Find the zeros of m^2+m-12=0

The zeros of m^2+m-12=0 are m=3,m=-4

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m^{2} + m - 12 = 0

m = 3, m = - 4

Solution steps

m^{2} + m - 12 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 1 \cdot ( - 12 )}{2 \cdot 1}

1^{2} - 4 \cdot 1 \cdot (- 12) = 7

m_{1, 2} = \frac{- 1 \pm 7}{2 \cdot 1}

Separate the solutions

m_{1} = \frac{- 1 + 7}{2 \cdot 1}, m_{2} = \frac{- 1 - 7}{2 \cdot 1}

m = \frac{- 1 + 7}{2 \cdot 1} : 3

m = \frac{- 1 - 7}{2 \cdot 1} : - 4

The solutions to the quadratic equation are:

m = 3, m = - 4

x^{2} + 3 x + 14 = 0

x, x^{2} + y^{2} + 4 = 0

3 (x - 2)^{2} = 0

x, x^{2} + y^{2} + 9 = 0

(0.75 \cdot 1 0^{4}) x = (- 3000 x + 15 - 1)^{2}

What are the solutions to the equation m^2+m-12=0 ?
The solutions to the equation m^2+m-12=0 are m=3,m=-4
Find the zeros of m^2+m-12=0
The zeros of m^2+m-12=0 are m=3,m=-4