What are the solutions to the equation x^2=6^2+2^2 ?

The solutions to the equation x^2=6^2+2^2 are x=2sqrt(10),x=-2sqrt(10)

Find the zeros of x^2=6^2+2^2

The zeros of x^2=6^2+2^2 are x=2sqrt(10),x=-2sqrt(10)

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x^{2} = 6^{2} + 2^{2}

x = 210, x = - 210

Solution steps

x^{2} = 6^{2} + 2^{2}

Simplify

6^{2} + 2^{2} : 40

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 40, x = - 40

40 = 210

- 40 = - 210

x = 210, x = - 210

3 (x - 4)^{2} = 2 (x - 4)

z^{2} - 0.75 z + 0.125 = 0

5 = (x - 3)^{2}

x^{2} = a^{2} + a^{2}

x^{2} + 3^{2} = 8^{2}

What are the solutions to the equation x^2=6^2+2^2 ?
The solutions to the equation x^2=6^2+2^2 are x=2sqrt(10),x=-2sqrt(10)
Find the zeros of x^2=6^2+2^2
The zeros of x^2=6^2+2^2 are x=2sqrt(10),x=-2sqrt(10)