What are the solutions to the equation (1-x)^2-9=0 ?

The solutions to the equation (1-x)^2-9=0 are x=-2,x=4

Find the zeros of (1-x)^2-9=0

The zeros of (1-x)^2-9=0 are x=-2,x=4

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(1 - x)^{2} - 9 = 0

x = - 2, x = 4

Solution steps

(1 - x)^{2} - 9 = 0

Move

9

to the right side

(1 - x)^{2} = 9

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

1 - x = 9 : x = - 2

Solve

1 - x = - 9 : x = 4

The solutions to the quadratic equation are:

x = - 2, x = 4

(x + 3)^{2} - 5 = 0

- 2 x^{2} + 4 x - 5 = 0

- 4 x^{2} + 3 x + 5 = 0

3 x^{2} + 10 x - 3 = 0

\frac{( y - 6 ) ^{2}}{4 ^{2}} - \frac{( 0 - 2 ) ^{2}}{3 ^{2}} = 1

What are the solutions to the equation (1-x)^2-9=0 ?
The solutions to the equation (1-x)^2-9=0 are x=-2,x=4
Find the zeros of (1-x)^2-9=0
The zeros of (1-x)^2-9=0 are x=-2,x=4