What are the solutions to the equation (x+3)^2-5=0 ?

The solutions to the equation (x+3)^2-5=0 are x=sqrt(5)-3,x=-sqrt(5)-3

Find the zeros of (x+3)^2-5=0

The zeros of (x+3)^2-5=0 are x=sqrt(5)-3,x=-sqrt(5)-3

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(x + 3)^{2} - 5 = 0

x = 5 - 3, x = - 5 - 3

Solution steps

(x + 3)^{2} - 5 = 0

Move

5

to the right side

(x + 3)^{2} = 5

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 3 = 5 : x = 5 - 3

Solve

x + 3 = - 5 : x = - 5 - 3

The solutions to the quadratic equation are:

x = 5 - 3, x = - 5 - 3

- 2 x^{2} + 4 x - 5 = 0

- 4 x^{2} + 3 x + 5 = 0

3 x^{2} + 10 x - 3 = 0

\frac{( y - 6 ) ^{2}}{4 ^{2}} - \frac{( 0 - 2 ) ^{2}}{3 ^{2}} = 1

- 5 x^{2} - 10 x - 130 = 0

What are the solutions to the equation (x+3)^2-5=0 ?
The solutions to the equation (x+3)^2-5=0 are x=sqrt(5)-3,x=-sqrt(5)-3
Find the zeros of (x+3)^2-5=0
The zeros of (x+3)^2-5=0 are x=sqrt(5)-3,x=-sqrt(5)-3