What are the solutions to the equation m^2-2m-5=0 ?

The solutions to the equation m^2-2m-5=0 are m=1+sqrt(6),m=1-sqrt(6)

Find the zeros of m^2-2m-5=0

The zeros of m^2-2m-5=0 are m=1+sqrt(6),m=1-sqrt(6)

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m^{2} - 2 m - 5 = 0

m = 1 + 6, m = 1 - 6

Solution steps

m^{2} - 2 m - 5 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 1 \cdot ( - 5 )}{2 \cdot 1}

(- 2)^{2} - 4 \cdot 1 \cdot (- 5) = 26

m_{1, 2} = \frac{- ( - 2 ) \pm 2 6}{2 \cdot 1}

Separate the solutions

m_{1} = \frac{- ( - 2 ) + 2 6}{2 \cdot 1}, m_{2} = \frac{- ( - 2 ) - 2 6}{2 \cdot 1}

m = \frac{- ( - 2 ) + 2 6}{2 \cdot 1} : 1 + 6

m = \frac{- ( - 2 ) - 2 6}{2 \cdot 1} : 1 - 6

The solutions to the quadratic equation are:

m = 1 + 6, m = 1 - 6

3 x^{2} - 4 x = 5

x^{2} - 4 = 32

4 x (x - 3) = - 9

x^{2} - 4 = 12

(x + 3)^{2} = 10

What are the solutions to the equation m^2-2m-5=0 ?
The solutions to the equation m^2-2m-5=0 are m=1+sqrt(6),m=1-sqrt(6)
Find the zeros of m^2-2m-5=0
The zeros of m^2-2m-5=0 are m=1+sqrt(6),m=1-sqrt(6)