What are the solutions to the equation x^2-4=12 ?

The solutions to the equation x^2-4=12 are x=4,x=-4

Find the zeros of x^2-4=12

The zeros of x^2-4=12 are x=4,x=-4

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x^{2} - 4 = 12

x = 4, x = - 4

Solution steps

x^{2} - 4 = 12

Move

4

to the right side

x^{2} = 16

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 16, x = - 16

16 = 4

- 16 = - 4

x = 4, x = - 4

(x + 3)^{2} = 10

(x + 3)^{2} = 20

4 n^{2} - 28 n + 48 = 0

x^{2} + 17 x - 18 = - 10

2 x^{2} + 7 x + 8 = 0

What are the solutions to the equation x^2-4=12 ?
The solutions to the equation x^2-4=12 are x=4,x=-4
Find the zeros of x^2-4=12
The zeros of x^2-4=12 are x=4,x=-4