What are the solutions to the equation 5x^2+20x+2=0 ?

The solutions to the equation 5x^2+20x+2=0 are x=(-10+3sqrt(10))/5 ,x=-(2sqrt(5)+3sqrt(2))/(sqrt(5))

Find the zeros of 5x^2+20x+2=0

The zeros of 5x^2+20x+2=0 are x=(-10+3sqrt(10))/5 ,x=-(2sqrt(5)+3sqrt(2))/(sqrt(5))

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5 x^{2} + 20 x + 2 = 0

x = \frac{- 10 + 3 10}{5}, x = - \frac{2 5 + 3 2}{5}

Decimal Notation

x = - 0.10263 \dots, x = - 3.89736 \dots

Solution steps

5 x^{2} + 20 x + 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 20 \pm 2 0 ^{2} - 4 \cdot 5 \cdot 2}{2 \cdot 5}

2 0^{2} - 4 \cdot 5 \cdot 2 = 610

x_{1, 2} = \frac{- 20 \pm 6 10}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- 20 + 6 10}{2 \cdot 5}, x_{2} = \frac{- 20 - 6 10}{2 \cdot 5}

x = \frac{- 20 + 6 10}{2 \cdot 5} : \frac{- 10 + 3 10}{5}

x = \frac{- 20 - 6 10}{2 \cdot 5} : - \frac{2 5 + 3 2}{5}

The solutions to the quadratic equation are:

x = \frac{- 10 + 3 10}{5}, x = - \frac{2 5 + 3 2}{5}

8 c^{2} + 2 c - 1 = 0

x^{2} - 10 x = 6

2 m^{2} + 2 m - 24 = 0

- x^{2} = 5

x^{2} + \frac{2}{3} x + 1

What are the solutions to the equation 5x^2+20x+2=0 ?
The solutions to the equation 5x^2+20x+2=0 are x=(-10+3sqrt(10))/5 ,x=-(2sqrt(5)+3sqrt(2))/(sqrt(5))
Find the zeros of 5x^2+20x+2=0
The zeros of 5x^2+20x+2=0 are x=(-10+3sqrt(10))/5 ,x=-(2sqrt(5)+3sqrt(2))/(sqrt(5))