What are the solutions to the equation 0=-16t^2+160t ?

The solutions to the equation 0=-16t^2+160t are t=0,t=10

Find the zeros of 0=-16t^2+160t

The zeros of 0=-16t^2+160t are t=0,t=10

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0 = - 16 t^{2} + 160 t

t = 0, t = 10

Solution steps

0 = - 16 t^{2} + 160 t

Switch sides

- 16 t^{2} + 160 t = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- 160 \pm 16 0 ^{2} - 4 ( - 16 ) \cdot 0}{2 ( - 16 )}

16 0^{2} - 4 (- 16) \cdot 0 = 160

t_{1, 2} = \frac{- 160 \pm 160}{2 ( - 16 )}

Separate the solutions

t_{1} = \frac{- 160 + 160}{2 ( - 16 )}, t_{2} = \frac{- 160 - 160}{2 ( - 16 )}

t = \frac{- 160 + 160}{2 ( - 16 )} : 0

t = \frac{- 160 - 160}{2 ( - 16 )} : 10

The solutions to the quadratic equation are:

t = 0, t = 10

320 = - 20 x^{2} + 320 x - 780

t^{2} + 2 t = 15

1.8 \cdot 1 0^{- 5} = \frac{x ^{2}}{0.5}

x^{2} + 20 x - 100 = 0

(18 - x)^{2} = (9 - x)^{2} + (16 - x)^{2}

What are the solutions to the equation 0=-16t^2+160t ?
The solutions to the equation 0=-16t^2+160t are t=0,t=10
Find the zeros of 0=-16t^2+160t
The zeros of 0=-16t^2+160t are t=0,t=10