What are the solutions to the equation 320=-20x^2+320x-780 ?

The solutions to the equation 320=-20x^2+320x-780 are x=5,x=11

Find the zeros of 320=-20x^2+320x-780

The zeros of 320=-20x^2+320x-780 are x=5,x=11

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

320 = - 20 x^{2} + 320 x - 780

x = 5, x = 11

Solution steps

320 = - 20 x^{2} + 320 x - 780

Switch sides

- 20 x^{2} + 320 x - 780 = 320

Move

320

to the left side

- 20 x^{2} + 320 x - 1100 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 320 \pm 32 0 ^{2} - 4 ( - 20 ) ( - 1100 )}{2 ( - 20 )}

32 0^{2} - 4 (- 20) (- 1100) = 120

x_{1, 2} = \frac{- 320 \pm 120}{2 ( - 20 )}

Separate the solutions

x_{1} = \frac{- 320 + 120}{2 ( - 20 )}, x_{2} = \frac{- 320 - 120}{2 ( - 20 )}

x = \frac{- 320 + 120}{2 ( - 20 )} : 5

x = \frac{- 320 - 120}{2 ( - 20 )} : 11

The solutions to the quadratic equation are:

x = 5, x = 11

t^{2} + 2 t = 15

1.8 \cdot 1 0^{- 5} = \frac{x ^{2}}{0.5}

x^{2} + 20 x - 100 = 0

(18 - x)^{2} = (9 - x)^{2} + (16 - x)^{2}

x^{2} - 18 x = - 72

What are the solutions to the equation 320=-20x^2+320x-780 ?
The solutions to the equation 320=-20x^2+320x-780 are x=5,x=11
Find the zeros of 320=-20x^2+320x-780
The zeros of 320=-20x^2+320x-780 are x=5,x=11