What are the solutions to the equation x^2+20x-100=0 ?

The solutions to the equation x^2+20x-100=0 are x=10(sqrt(2)-1),x=-10(1+sqrt(2))

Find the zeros of x^2+20x-100=0

The zeros of x^2+20x-100=0 are x=10(sqrt(2)-1),x=-10(1+sqrt(2))

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x^{2} + 20 x - 100 = 0

x = 10 (2 - 1), x = - 10 (1 + 2)

Decimal Notation

x = 4.14213 \dots, x = - 24.14213 \dots

Solution steps

x^{2} + 20 x - 100 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 20 \pm 2 0 ^{2} - 4 \cdot 1 \cdot ( - 100 )}{2 \cdot 1}

2 0^{2} - 4 \cdot 1 \cdot (- 100) = 202

x_{1, 2} = \frac{- 20 \pm 20 2}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 20 + 20 2}{2 \cdot 1}, x_{2} = \frac{- 20 - 20 2}{2 \cdot 1}

x = \frac{- 20 + 20 2}{2 \cdot 1} : 10 (2 - 1)

x = \frac{- 20 - 20 2}{2 \cdot 1} : - 10 (1 + 2)

The solutions to the quadratic equation are:

x = 10 (2 - 1), x = - 10 (1 + 2)

(18 - x)^{2} = (9 - x)^{2} + (16 - x)^{2}

x^{2} - 18 x = - 72

7 x^{2} = - 560

9 x^{2} + 64 = 0

x, 2 x^{2} - 2 x y + 2 y^{2} = 1

What are the solutions to the equation x^2+20x-100=0 ?
The solutions to the equation x^2+20x-100=0 are x=10(sqrt(2)-1),x=-10(1+sqrt(2))
Find the zeros of x^2+20x-100=0
The zeros of x^2+20x-100=0 are x=10(sqrt(2)-1),x=-10(1+sqrt(2))