What are the solutions to the equation x^2-18x=-72 ?

The solutions to the equation x^2-18x=-72 are x=12,x=6

Find the zeros of x^2-18x=-72

The zeros of x^2-18x=-72 are x=12,x=6

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x^{2} - 18 x = - 72

x = 12, x = 6

Solution steps

x^{2} - 18 x = - 72

Move

72

to the left side

x^{2} - 18 x + 72 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 18 ) \pm ( - 18 ) ^{2} - 4 \cdot 1 \cdot 72}{2 \cdot 1}

(- 18)^{2} - 4 \cdot 1 \cdot 72 = 6

x_{1, 2} = \frac{- ( - 18 ) \pm 6}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 18 ) + 6}{2 \cdot 1}, x_{2} = \frac{- ( - 18 ) - 6}{2 \cdot 1}

x = \frac{- ( - 18 ) + 6}{2 \cdot 1} : 12

x = \frac{- ( - 18 ) - 6}{2 \cdot 1} : 6

The solutions to the quadratic equation are:

x = 12, x = 6

7 x^{2} = - 560

9 x^{2} + 64 = 0

x, 2 x^{2} - 2 x y + 2 y^{2} = 1

m^{2} + 8 m + 7 = 0

4 x^{2} + x + 8 = 0

What are the solutions to the equation x^2-18x=-72 ?
The solutions to the equation x^2-18x=-72 are x=12,x=6
Find the zeros of x^2-18x=-72
The zeros of x^2-18x=-72 are x=12,x=6