What are the solutions to the equation 9x^2+64=0 ?

The solutions to the equation 9x^2+64=0 are x= 8/3 i,x=-8/3 i

Find the zeros of 9x^2+64=0

The zeros of 9x^2+64=0 are x= 8/3 i,x=-8/3 i

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9 x^{2} + 64 = 0

x = \frac{8}{3} i, x = - \frac{8}{3} i

Solution steps

9 x^{2} + 64 = 0

Move

64

to the right side

9 x^{2} = - 64

Divide both sides by

9

x^{2} = - \frac{64}{9}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - \frac{64}{9}, x = - - \frac{64}{9}

- \frac{64}{9} = \frac{8}{3} i

- - \frac{64}{9} = - \frac{8}{3} i

x = \frac{8}{3} i, x = - \frac{8}{3} i

x, 2 x^{2} - 2 x y + 2 y^{2} = 1

m^{2} + 8 m + 7 = 0

4 x^{2} + x + 8 = 0

2 x^{2} + \frac{5}{2} x - \frac{3}{4} = 0

(x - 4) (x - 7) = 0

What are the solutions to the equation 9x^2+64=0 ?
The solutions to the equation 9x^2+64=0 are x= 8/3 i,x=-8/3 i
Find the zeros of 9x^2+64=0
The zeros of 9x^2+64=0 are x= 8/3 i,x=-8/3 i