What are the solutions to the equation 2x^2+5/2 x-3/4 =0 ?

The solutions to the equation 2x^2+5/2 x-3/4 =0 are x= 1/4 ,x=-3/2

Find the zeros of 2x^2+5/2 x-3/4 =0

The zeros of 2x^2+5/2 x-3/4 =0 are x= 1/4 ,x=-3/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2 x^{2} + \frac{5}{2} x - \frac{3}{4} = 0

x = \frac{1}{4}, x = - \frac{3}{2}

Decimal Notation

x = 0.25, x = - 1.5

Solution steps

2 x^{2} + \frac{5}{2} x - \frac{3}{4} = 0

Find Least Common Multiplier of

2, 4 : 4

Multiply by LCM=

4

2 x^{2} \cdot 4 + \frac{5}{2} x \cdot 4 - \frac{3}{4} \cdot 4 = 0 \cdot 4

Simplify

8 x^{2} + 10 x - 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 8 ( - 3 )}{2 \cdot 8}

1 0^{2} - 4 \cdot 8 (- 3) = 14

x_{1, 2} = \frac{- 10 \pm 14}{2 \cdot 8}

Separate the solutions

x_{1} = \frac{- 10 + 14}{2 \cdot 8}, x_{2} = \frac{- 10 - 14}{2 \cdot 8}

x = \frac{- 10 + 14}{2 \cdot 8} : \frac{1}{4}

x = \frac{- 10 - 14}{2 \cdot 8} : - \frac{3}{2}

The solutions to the quadratic equation are:

x = \frac{1}{4}, x = - \frac{3}{2}

(x - 4) (x - 7) = 0

x, 1 - 2 x y + y^{2} = - x^{2} - 1 + 2 x y

3 x^{2} - 16 x + 23 = 0

3 x^{2} = 5 + 8 x

(x + 7)^{2} = 16

What are the solutions to the equation 2x^2+5/2 x-3/4 =0 ?
The solutions to the equation 2x^2+5/2 x-3/4 =0 are x= 1/4 ,x=-3/2
Find the zeros of 2x^2+5/2 x-3/4 =0
The zeros of 2x^2+5/2 x-3/4 =0 are x= 1/4 ,x=-3/2