What are the solutions to the equation 9x^2+6x-3=0 ?

The solutions to the equation 9x^2+6x-3=0 are x= 1/3 ,x=-1

Find the zeros of 9x^2+6x-3=0

The zeros of 9x^2+6x-3=0 are x= 1/3 ,x=-1

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9 x^{2} + 6 x - 3 = 0

x = \frac{1}{3}, x = - 1

Decimal Notation

x = 0.33333 \dots, x = - 1

Solution steps

9 x^{2} + 6 x - 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 9 ( - 3 )}{2 \cdot 9}

6^{2} - 4 \cdot 9 (- 3) = 12

x_{1, 2} = \frac{- 6 \pm 12}{2 \cdot 9}

Separate the solutions

x_{1} = \frac{- 6 + 12}{2 \cdot 9}, x_{2} = \frac{- 6 - 12}{2 \cdot 9}

x = \frac{- 6 + 12}{2 \cdot 9} : \frac{1}{3}

x = \frac{- 6 - 12}{2 \cdot 9} : - 1

The solutions to the quadratic equation are:

x = \frac{1}{3}, x = - 1

24 x^{2} + 48 x = 0

ab x^{2} - (b - 2 a) x - 2 = 0

x^{2} - 3 = 0

x, 36 x^{2} + 64 y^{2} + 360 x - 512 y + 1924 = 0

x^{2} + 8 x + 9 = - 9

What are the solutions to the equation 9x^2+6x-3=0 ?
The solutions to the equation 9x^2+6x-3=0 are x= 1/3 ,x=-1
Find the zeros of 9x^2+6x-3=0
The zeros of 9x^2+6x-3=0 are x= 1/3 ,x=-1