What are the solutions to the equation 24x^2+48x=0 ?

The solutions to the equation 24x^2+48x=0 are x=0,x=-2

Find the zeros of 24x^2+48x=0

The zeros of 24x^2+48x=0 are x=0,x=-2

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24 x^{2} + 48 x = 0

x = 0, x = - 2

Solution steps

24 x^{2} + 48 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 48 \pm 4 8 ^{2} - 4 \cdot 24 \cdot 0}{2 \cdot 24}

4 8^{2} - 4 \cdot 24 \cdot 0 = 48

x_{1, 2} = \frac{- 48 \pm 48}{2 \cdot 24}

Separate the solutions

x_{1} = \frac{- 48 + 48}{2 \cdot 24}, x_{2} = \frac{- 48 - 48}{2 \cdot 24}

x = \frac{- 48 + 48}{2 \cdot 24} : 0

x = \frac{- 48 - 48}{2 \cdot 24} : - 2

The solutions to the quadratic equation are:

x = 0, x = - 2

ab x^{2} - (b - 2 a) x - 2 = 0

x^{2} - 3 = 0

x, 36 x^{2} + 64 y^{2} + 360 x - 512 y + 1924 = 0

x^{2} + 8 x + 9 = - 9

x^{2} + 50 x + 336 = 0

What are the solutions to the equation 24x^2+48x=0 ?
The solutions to the equation 24x^2+48x=0 are x=0,x=-2
Find the zeros of 24x^2+48x=0
The zeros of 24x^2+48x=0 are x=0,x=-2