What are the solutions to the equation 5x^2-3x+5=0 ?

The solutions to the equation 5x^2-3x+5=0 are x= 3/10+i(sqrt(91))/(10),x= 3/10-i(sqrt(91))/(10)

Find the zeros of 5x^2-3x+5=0

The zeros of 5x^2-3x+5=0 are x= 3/10+i(sqrt(91))/(10),x= 3/10-i(sqrt(91))/(10)

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5 x^{2} - 3 x + 5 = 0

x = \frac{3}{10} + i \frac{91}{10}, x = \frac{3}{10} - i \frac{91}{10}

Solution steps

5 x^{2} - 3 x + 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 5 \cdot 5}{2 \cdot 5}

Simplify

(- 3)^{2} - 4 \cdot 5 \cdot 5 : 91 i

x_{1, 2} = \frac{- ( - 3 ) \pm 91 i}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- ( - 3 ) + 91 i}{2 \cdot 5}, x_{2} = \frac{- ( - 3 ) - 91 i}{2 \cdot 5}

x = \frac{- ( - 3 ) + 91 i}{2 \cdot 5} : \frac{3}{10} + i \frac{91}{10}

x = \frac{- ( - 3 ) - 91 i}{2 \cdot 5} : \frac{3}{10} - i \frac{91}{10}

The solutions to the quadratic equation are:

x = \frac{3}{10} + i \frac{91}{10}, x = \frac{3}{10} - i \frac{91}{10}

3 x^{2} + x = 14

4 x^{2} + 8 x

0 = 3 x^{2} - 27

4 x^{2} + 6 x

2 (t - 3)^{2} - 72 = 0

What are the solutions to the equation 5x^2-3x+5=0 ?
The solutions to the equation 5x^2-3x+5=0 are x= 3/10+i(sqrt(91))/(10),x= 3/10-i(sqrt(91))/(10)
Find the zeros of 5x^2-3x+5=0
The zeros of 5x^2-3x+5=0 are x= 3/10+i(sqrt(91))/(10),x= 3/10-i(sqrt(91))/(10)