What are the solutions to the equation x^2+35=5x ?

The solutions to the equation x^2+35=5x are x= 5/2+i(sqrt(115))/2 ,x= 5/2-i(sqrt(115))/2

Find the zeros of x^2+35=5x

The zeros of x^2+35=5x are x= 5/2+i(sqrt(115))/2 ,x= 5/2-i(sqrt(115))/2

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x^{2} + 35 = 5 x

x = \frac{5}{2} + i \frac{115}{2}, x = \frac{5}{2} - i \frac{115}{2}

Solution steps

x^{2} + 35 = 5 x

Move

5 x

to the left side

x^{2} + 35 - 5 x = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} - 5 x + 35 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 1 \cdot 35}{2 \cdot 1}

Simplify

(- 5)^{2} - 4 \cdot 1 \cdot 35 : 115 i

x_{1, 2} = \frac{- ( - 5 ) \pm 115 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 5 ) + 115 i}{2 \cdot 1}, x_{2} = \frac{- ( - 5 ) - 115 i}{2 \cdot 1}

x = \frac{- ( - 5 ) + 115 i}{2 \cdot 1} : \frac{5}{2} + i \frac{115}{2}

x = \frac{- ( - 5 ) - 115 i}{2 \cdot 1} : \frac{5}{2} - i \frac{115}{2}

The solutions to the quadratic equation are:

x = \frac{5}{2} + i \frac{115}{2}, x = \frac{5}{2} - i \frac{115}{2}

ln (e^{2}) = x^{2} - 1

x, 3 x^{2} + m x + 8 = 7 x - 16

1 - 4 x (1 - x) = 0

7 a^{2} - 19 a + 10 = 0

- 2 x^{2} + 8 x - 4

What are the solutions to the equation x^2+35=5x ?
The solutions to the equation x^2+35=5x are x= 5/2+i(sqrt(115))/2 ,x= 5/2-i(sqrt(115))/2
Find the zeros of x^2+35=5x
The zeros of x^2+35=5x are x= 5/2+i(sqrt(115))/2 ,x= 5/2-i(sqrt(115))/2