What are the solutions to the equation (x+1)^2=-121 ?

The solutions to the equation (x+1)^2=-121 are x=11i-1,x=-11i-1

Find the zeros of (x+1)^2=-121

The zeros of (x+1)^2=-121 are x=11i-1,x=-11i-1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(x + 1)^{2} = - 121

x = 11 i - 1, x = - 11 i - 1

Solution steps

(x + 1)^{2} = - 121

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 1 = - 121 : x = 11 i - 1

Solve

x + 1 = - - 121 : x = - 11 i - 1

The solutions to the quadratic equation are:

x = 11 i - 1, x = - 11 i - 1

x^{2} + 21 x + 20 = 0

x^{2} + 11 x + 5 = 0

x, 7 x - y + 3 x y = x^{2} + y^{2}

(4 + x) (5 - 2 x) = (2 x + 1) (x - 2)

x, 6 x^{2} - y^{2} + 24 x y - 12 x + 26 y + 11 = 0

What are the solutions to the equation (x+1)^2=-121 ?
The solutions to the equation (x+1)^2=-121 are x=11i-1,x=-11i-1
Find the zeros of (x+1)^2=-121
The zeros of (x+1)^2=-121 are x=11i-1,x=-11i-1