What are the solutions to the equation -2x^2=17 ?

The solutions to the equation -2x^2=17 are x=sqrt(17/2)i,x=-sqrt(17/2)i

Find the zeros of -2x^2=17

The zeros of -2x^2=17 are x=sqrt(17/2)i,x=-sqrt(17/2)i

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- 2 x^{2} = 17

x = \frac{17}{2} i, x = - \frac{17}{2} i

Solution steps

- 2 x^{2} = 17

Divide both sides by

- 2

x^{2} = - \frac{17}{2}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - \frac{17}{2}, x = - - \frac{17}{2}

- \frac{17}{2} = \frac{17}{2} i

- - \frac{17}{2} = - \frac{17}{2} i

x = \frac{17}{2} i, x = - \frac{17}{2} i

x^{2} + 2 x - 8 = 0

y^{2} - 7 y + 6 = 0

2 x^{2} - 15 x + 13 = 1 - x^{2}

3^{2} + b^{2} = 7^{2}

2 x^{2} - 5 x + 67 = 0

What are the solutions to the equation -2x^2=17 ?
The solutions to the equation -2x^2=17 are x=sqrt(17/2)i,x=-sqrt(17/2)i
Find the zeros of -2x^2=17
The zeros of -2x^2=17 are x=sqrt(17/2)i,x=-sqrt(17/2)i