What are the solutions to the equation completesquare x^2+2x-5=0 ?

The solutions to the equation completesquare x^2+2x-5=0 are x=sqrt(6)-1,x=-sqrt(6)-1

Find the zeros of completesquare x^2+2x-5=0

The zeros of completesquare x^2+2x-5=0 are x=sqrt(6)-1,x=-sqrt(6)-1

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x^{2} + 2 x - 5 = 0

x = 6 - 1, x = - 6 - 1

Decimal Notation

x = 1.44948 \dots, x = - 3.44948 \dots

Solution steps

x^{2} + 2 x - 5 = 0

Move

5

to the right side

x^{2} + 2 x = 5

Rewrite in the form

(x + a)^{2} = b

(x + 1)^{2} = 6

For

the solutions are

f (x) = a, - a

Solve

x + 1 = 6 : x = 6 - 1

Solve

x + 1 = - 6 : x = - 6 - 1

The solutions to the quadratic equation are:

x = 6 - 1, x = - 6 - 1

6 x^{2} - 8 x - 30 = 0

- 7 x + x^{2} = - 3 x^{2} + 6

\frac{1}{4} x^{2} + 3 x = x - 4

- x^{2} + 8 x + 1 = 0

x^{2} - x = 7

What are the solutions to the equation completesquare x^2+2x-5=0 ?
The solutions to the equation completesquare x^2+2x-5=0 are x=sqrt(6)-1,x=-sqrt(6)-1
Find the zeros of completesquare x^2+2x-5=0
The zeros of completesquare x^2+2x-5=0 are x=sqrt(6)-1,x=-sqrt(6)-1