What are the solutions to the equation -x^2+6x=x+4 ?

The solutions to the equation -x^2+6x=x+4 are x=1,x=4

Find the zeros of -x^2+6x=x+4

The zeros of -x^2+6x=x+4 are x=1,x=4

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- x^{2} + 6 x = x + 4

x = 1, x = 4

Solution steps

- x^{2} + 6 x = x + 4

Move

4

to the left side

- x^{2} + 6 x - 4 = x

Move

x

to the left side

- x^{2} + 5 x - 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 ( - 1 ) ( - 4 )}{2 ( - 1 )}

5^{2} - 4 (- 1) (- 4) = 3

x_{1, 2} = \frac{- 5 \pm 3}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 5 + 3}{2 ( - 1 )}, x_{2} = \frac{- 5 - 3}{2 ( - 1 )}

x = \frac{- 5 + 3}{2 ( - 1 )} : 1

x = \frac{- 5 - 3}{2 ( - 1 )} : 4

The solutions to the quadratic equation are:

x = 1, x = 4

v^{2} + 2 v - 15 = 0

6 x^{2} + 2 x - 8 = 0

x^{2} - 81 = 0

4 (x^{2} + 1) = 3 (x^{2} + 3) + 4

4 x^{2} - 16 x

What are the solutions to the equation -x^2+6x=x+4 ?
The solutions to the equation -x^2+6x=x+4 are x=1,x=4
Find the zeros of -x^2+6x=x+4
The zeros of -x^2+6x=x+4 are x=1,x=4