What are the solutions to the equation (-1-x)^2=0 ?

The solutions to the equation (-1-x)^2=0 are x=-1

Find the zeros of (-1-x)^2=0

The zeros of (-1-x)^2=0 are x=-1

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(- 1 - x)^{2} = 0

x = - 1

Solution steps

(- 1 - x)^{2} = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

Solve

- 1 - x = 0 : x = - 1

The solution to the quadratic equation is:

x = - 1

x, \frac{x ^{2}}{9} + \frac{y ^{2}}{9} + \frac{z ^{2}}{9} = 1

2 a^{2} - 8 a + 3 = 0

\frac{1}{4} x^{2} + 2 x + 4 = 0

x (x + 5) = 84

x, \frac{( x - 2 ) ^{2}}{9} + \frac{( y + 3 ) ^{2}}{25} = 1

What are the solutions to the equation (-1-x)^2=0 ?
The solutions to the equation (-1-x)^2=0 are x=-1
Find the zeros of (-1-x)^2=0
The zeros of (-1-x)^2=0 are x=-1