What are the solutions to the equation -2x^2-28x+30=0 ?

The solutions to the equation -2x^2-28x+30=0 are x=-15,x=1

Find the zeros of -2x^2-28x+30=0

The zeros of -2x^2-28x+30=0 are x=-15,x=1

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- 2 x^{2} - 28 x + 30 = 0

x = - 15, x = 1

Solution steps

- 2 x^{2} - 28 x + 30 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 28 ) \pm ( - 28 ) ^{2} - 4 ( - 2 ) \cdot 30}{2 ( - 2 )}

(- 28)^{2} - 4 (- 2) \cdot 30 = 32

x_{1, 2} = \frac{- ( - 28 ) \pm 32}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- ( - 28 ) + 32}{2 ( - 2 )}, x_{2} = \frac{- ( - 28 ) - 32}{2 ( - 2 )}

x = \frac{- ( - 28 ) + 32}{2 ( - 2 )} : - 15

x = \frac{- ( - 28 ) - 32}{2 ( - 2 )} : 1

The solutions to the quadratic equation are:

x = - 15, x = 1

(5 x^{2} + x)^{2} = (3 x + 3)^{2}

x, x^{2} + y^{2} - 6 x - 8 y = - 25

x - x^{2}

(x - 1) (x - 3) = - 1

6 a^{2} - 4 a - 22 = 0

What are the solutions to the equation -2x^2-28x+30=0 ?
The solutions to the equation -2x^2-28x+30=0 are x=-15,x=1
Find the zeros of -2x^2-28x+30=0
The zeros of -2x^2-28x+30=0 are x=-15,x=1