What are the solutions to the equation (y-2)^2=-8y ?

The solutions to the equation (y-2)^2=-8y are y=-2

Find the zeros of (y-2)^2=-8y

The zeros of (y-2)^2=-8y are y=-2

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Popular >

(y - 2)^{2} = - 8 y

y = - 2

Solution steps

(y - 2)^{2} = - 8 y

Expand

(y - 2)^{2} : y^{2} - 4 y + 4

y^{2} - 4 y + 4 = - 8 y

Move

8 y

to the left side

y^{2} + 4 y + 4 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 1 \cdot 4}{2 \cdot 1}

4^{2} - 4 \cdot 1 \cdot 4 = 0

y_{1, 2} = \frac{- 4 \pm 0}{2 \cdot 1}

y = \frac{- 4}{2 \cdot 1}

\frac{- 4}{2 \cdot 1} = - 2

y = - 2

The solution to the quadratic equation is:

y = - 2

2 x^{2} + 10 = 9 x

z^{2} + 2 z + 10 = 0

4 x^{2} - 8 x - 9 = 0

- 3 x^{2} - 16 x + 84 = 0

125 - x^{2} = x^{2} + 15 x

What are the solutions to the equation (y-2)^2=-8y ?
The solutions to the equation (y-2)^2=-8y are y=-2
Find the zeros of (y-2)^2=-8y
The zeros of (y-2)^2=-8y are y=-2