What are the solutions to the equation 8x^2+5x-1=0 ?

The solutions to the equation 8x^2+5x-1=0 are x=(-5+sqrt(57))/(16),x=(-5-sqrt(57))/(16)

Find the zeros of 8x^2+5x-1=0

The zeros of 8x^2+5x-1=0 are x=(-5+sqrt(57))/(16),x=(-5-sqrt(57))/(16)

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8 x^{2} + 5 x - 1 = 0

x = \frac{- 5 + 57}{16}, x = \frac{- 5 - 57}{16}

Decimal Notation

x = 0.15936 \dots, x = - 0.78436 \dots

Solution steps

8 x^{2} + 5 x - 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 8 ( - 1 )}{2 \cdot 8}

5^{2} - 4 \cdot 8 (- 1) = 57

x_{1, 2} = \frac{- 5 \pm 57}{2 \cdot 8}

Separate the solutions

x_{1} = \frac{- 5 + 57}{2 \cdot 8}, x_{2} = \frac{- 5 - 57}{2 \cdot 8}

x = \frac{- 5 + 57}{2 \cdot 8} : \frac{- 5 + 57}{16}

x = \frac{- 5 - 57}{2 \cdot 8} : \frac{- 5 - 57}{16}

The solutions to the quadratic equation are:

x = \frac{- 5 + 57}{16}, x = \frac{- 5 - 57}{16}

4 m^{2} = - 6 + 5 m

(6 - x) (- 6 - x) + 36 = 0

4 x^{2} + 20 x + 25 = 0

m^{2} + 3 m - 4 = 0

x, x^{2} - 2 y^{2} + 2 x + 8 y - 7 = 0

What are the solutions to the equation 8x^2+5x-1=0 ?
The solutions to the equation 8x^2+5x-1=0 are x=(-5+sqrt(57))/(16),x=(-5-sqrt(57))/(16)
Find the zeros of 8x^2+5x-1=0
The zeros of 8x^2+5x-1=0 are x=(-5+sqrt(57))/(16),x=(-5-sqrt(57))/(16)