What are the solutions to the equation 4m^2=-6+5m ?

The solutions to the equation 4m^2=-6+5m are m= 5/8+i(sqrt(71))/8 ,m= 5/8-i(sqrt(71))/8

Find the zeros of 4m^2=-6+5m

The zeros of 4m^2=-6+5m are m= 5/8+i(sqrt(71))/8 ,m= 5/8-i(sqrt(71))/8

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4 m^{2} = - 6 + 5 m

m = \frac{5}{8} + i \frac{71}{8}, m = \frac{5}{8} - i \frac{71}{8}

Solution steps

4 m^{2} = - 6 + 5 m

Move

5 m

to the left side

4 m^{2} - 5 m = - 6

Move

6

to the left side

4 m^{2} - 5 m + 6 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 4 \cdot 6}{2 \cdot 4}

Simplify

(- 5)^{2} - 4 \cdot 4 \cdot 6 : 71 i

m_{1, 2} = \frac{- ( - 5 ) \pm 71 i}{2 \cdot 4}

Separate the solutions

m_{1} = \frac{- ( - 5 ) + 71 i}{2 \cdot 4}, m_{2} = \frac{- ( - 5 ) - 71 i}{2 \cdot 4}

m = \frac{- ( - 5 ) + 71 i}{2 \cdot 4} : \frac{5}{8} + i \frac{71}{8}

m = \frac{- ( - 5 ) - 71 i}{2 \cdot 4} : \frac{5}{8} - i \frac{71}{8}

The solutions to the quadratic equation are:

m = \frac{5}{8} + i \frac{71}{8}, m = \frac{5}{8} - i \frac{71}{8}

(6 - x) (- 6 - x) + 36 = 0

4 x^{2} + 20 x + 25 = 0

m^{2} + 3 m - 4 = 0

x, x^{2} - 2 y^{2} + 2 x + 8 y - 7 = 0

(x + 3) (x - 4) = 8

What are the solutions to the equation 4m^2=-6+5m ?
The solutions to the equation 4m^2=-6+5m are m= 5/8+i(sqrt(71))/8 ,m= 5/8-i(sqrt(71))/8
Find the zeros of 4m^2=-6+5m
The zeros of 4m^2=-6+5m are m= 5/8+i(sqrt(71))/8 ,m= 5/8-i(sqrt(71))/8