What are the solutions to the equation completesquare 4x^2+20x+25=0 ?

The solutions to the equation completesquare 4x^2+20x+25=0 are x=-5/2

Find the zeros of completesquare 4x^2+20x+25=0

The zeros of completesquare 4x^2+20x+25=0 are x=-5/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

4 x^{2} + 20 x + 25 = 0

x = - \frac{5}{2}

Decimal Notation

x = - 2.5

Solution steps

4 x^{2} + 20 x + 25 = 0

Move

25

to the right side

4 x^{2} + 20 x = - 25

Divide both sides by

4

\frac{4 x ^{2} + 20 x}{4} = \frac{- 25}{4}

x^{2} + 5 x = - \frac{25}{4}

Rewrite in the form

(x + a)^{2} = b

(x + \frac{5}{2})^{2} = 0

Solve

x + \frac{5}{2} = 0 : x = - \frac{5}{2}

The solution to the quadratic equation is:

x = - \frac{5}{2}

m^{2} + 3 m - 4 = 0

x, x^{2} - 2 y^{2} + 2 x + 8 y - 7 = 0

(x + 3) (x - 4) = 8

2 r^{2} + 2 r + 1 = 0

x^{2} - 14 x + 229 = 0

What are the solutions to the equation completesquare 4x^2+20x+25=0 ?
The solutions to the equation completesquare 4x^2+20x+25=0 are x=-5/2
Find the zeros of completesquare 4x^2+20x+25=0
The zeros of completesquare 4x^2+20x+25=0 are x=-5/2