What are the solutions to the equation solvefor y,x^3-2y^2-9=x ?

The solutions to the equation solvefor y,x^3-2y^2-9=x are y=isqrt((x-x^3+9)/2),y=-isqrt((x-x^3+9)/2)

Find the zeros of solvefor y,x^3-2y^2-9=x

The zeros of solvefor y,x^3-2y^2-9=x are y=isqrt((x-x^3+9)/2),y=-isqrt((x-x^3+9)/2)

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solve for

y, x^{3} - 2 y^{2} - 9 = x

y = i \frac{x - x ^{3} + 9}{2}, y = - i \frac{x - x ^{3} + 9}{2}

Solution steps

x^{3} - 2 y^{2} - 9 = x

Move

x^{3}

to the right side

- 2 y^{2} - 9 = x - x^{3}

Move

9

to the right side

- 2 y^{2} = x - x^{3} + 9

Divide both sides by

- 2

y^{2} = - \frac{x - x ^{3} + 9}{2}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

y = - \frac{x - x ^{3} + 9}{2}, y = - - \frac{x - x ^{3} + 9}{2}

Simplify

- \frac{x - x ^{3} + 9}{2} : i \frac{x - x ^{3} + 9}{2}

Simplify

- - \frac{x - x ^{3} + 9}{2} : - i \frac{x - x ^{3} + 9}{2}

y = i \frac{x - x ^{3} + 9}{2}, y = - i \frac{x - x ^{3} + 9}{2}

\frac{9}{16} - \frac{x ^{2}}{81} = 0

0.4 x^{2} + 1.5 x - 1.3 = 0

s^{2} + s + 5

(- \frac{11}{4})^{2} + y^{2} = 1

x^{2} + 9 x + 18 = 0

What are the solutions to the equation solvefor y,x^3-2y^2-9=x ?
The solutions to the equation solvefor y,x^3-2y^2-9=x are y=isqrt((x-x^3+9)/2),y=-isqrt((x-x^3+9)/2)
Find the zeros of solvefor y,x^3-2y^2-9=x
The zeros of solvefor y,x^3-2y^2-9=x are y=isqrt((x-x^3+9)/2),y=-isqrt((x-x^3+9)/2)