What are the solutions to the equation 0.4x^2+1.5x-1.3=0 ?

The solutions to the equation 0.4x^2+1.5x-1.3=0 are x=(-15+sqrt(433))/8 ,x=(-15-sqrt(433))/8

Find the zeros of 0.4x^2+1.5x-1.3=0

The zeros of 0.4x^2+1.5x-1.3=0 are x=(-15+sqrt(433))/8 ,x=(-15-sqrt(433))/8

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0.4 x^{2} + 1.5 x - 1.3 = 0

x = \frac{- 15 + 433}{8}, x = \frac{- 15 - 433}{8}

Decimal Notation

x = 0.72608 \dots, x = - 4.47608 \dots

Solution steps

0.4 x^{2} + 1.5 x - 1.3 = 0

Multiply both sides by

10

4 x^{2} + 15 x - 13 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 15 \pm 1 5 ^{2} - 4 \cdot 4 ( - 13 )}{2 \cdot 4}

1 5^{2} - 4 \cdot 4 (- 13) = 433

x_{1, 2} = \frac{- 15 \pm 433}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 15 + 433}{2 \cdot 4}, x_{2} = \frac{- 15 - 433}{2 \cdot 4}

x = \frac{- 15 + 433}{2 \cdot 4} : \frac{- 15 + 433}{8}

x = \frac{- 15 - 433}{2 \cdot 4} : \frac{- 15 - 433}{8}

The solutions to the quadratic equation are:

x = \frac{- 15 + 433}{8}, x = \frac{- 15 - 433}{8}

s^{2} + s + 5

(- \frac{11}{4})^{2} + y^{2} = 1

x^{2} + 9 x + 18 = 0

x^{2} - 7.2 x + 12.8 = 0

5 x = (2 x + 1)^{2}

What are the solutions to the equation 0.4x^2+1.5x-1.3=0 ?
The solutions to the equation 0.4x^2+1.5x-1.3=0 are x=(-15+sqrt(433))/8 ,x=(-15-sqrt(433))/8
Find the zeros of 0.4x^2+1.5x-1.3=0
The zeros of 0.4x^2+1.5x-1.3=0 are x=(-15+sqrt(433))/8 ,x=(-15-sqrt(433))/8