What are the solutions to the equation 3x^2+174=48x ?

The solutions to the equation 3x^2+174=48x are x=8+sqrt(6),x=8-sqrt(6)

Find the zeros of 3x^2+174=48x

The zeros of 3x^2+174=48x are x=8+sqrt(6),x=8-sqrt(6)

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3 x^{2} + 174 = 48 x

x = 8 + 6, x = 8 - 6

Decimal Notation

x = 10.44948 \dots, x = 5.55051 \dots

Solution steps

3 x^{2} + 174 = 48 x

Move

48 x

to the left side

3 x^{2} + 174 - 48 x = 0

Write in the standard form

a x^{2} + b x + c = 0

3 x^{2} - 48 x + 174 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 48 ) \pm ( - 48 ) ^{2} - 4 \cdot 3 \cdot 174}{2 \cdot 3}

(- 48)^{2} - 4 \cdot 3 \cdot 174 = 66

x_{1, 2} = \frac{- ( - 48 ) \pm 6 6}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 48 ) + 6 6}{2 \cdot 3}, x_{2} = \frac{- ( - 48 ) - 6 6}{2 \cdot 3}

x = \frac{- ( - 48 ) + 6 6}{2 \cdot 3} : 8 + 6

x = \frac{- ( - 48 ) - 6 6}{2 \cdot 3} : 8 - 6

The solutions to the quadratic equation are:

x = 8 + 6, x = 8 - 6

- 2 x^{2} + 3 x - 4 = 0

x^{2} + 2 x - 24

6 x^{2} = 6

x (x + 4) = 165

x, f = 3 x^{2} - x + 52 f (- 3) - f (4)

What are the solutions to the equation 3x^2+174=48x ?
The solutions to the equation 3x^2+174=48x are x=8+sqrt(6),x=8-sqrt(6)
Find the zeros of 3x^2+174=48x
The zeros of 3x^2+174=48x are x=8+sqrt(6),x=8-sqrt(6)