What are the solutions to the equation -2x^2+3x-4=0 ?

The solutions to the equation -2x^2+3x-4=0 are x= 3/4-i(sqrt(23))/4 ,x= 3/4+i(sqrt(23))/4

Find the zeros of -2x^2+3x-4=0

The zeros of -2x^2+3x-4=0 are x= 3/4-i(sqrt(23))/4 ,x= 3/4+i(sqrt(23))/4

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- 2 x^{2} + 3 x - 4 = 0

x = \frac{3}{4} - i \frac{23}{4}, x = \frac{3}{4} + i \frac{23}{4}

Solution steps

- 2 x^{2} + 3 x - 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 ( - 2 ) ( - 4 )}{2 ( - 2 )}

Simplify

3^{2} - 4 (- 2) (- 4) : 23 i

x_{1, 2} = \frac{- 3 \pm 23 i}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- 3 + 23 i}{2 ( - 2 )}, x_{2} = \frac{- 3 - 23 i}{2 ( - 2 )}

x = \frac{- 3 + 23 i}{2 ( - 2 )} : \frac{3}{4} - i \frac{23}{4}

x = \frac{- 3 - 23 i}{2 ( - 2 )} : \frac{3}{4} + i \frac{23}{4}

The solutions to the quadratic equation are:

x = \frac{3}{4} - i \frac{23}{4}, x = \frac{3}{4} + i \frac{23}{4}

x^{2} + 2 x - 24

6 x^{2} = 6

x (x + 4) = 165

x, f = 3 x^{2} - x + 52 f (- 3) - f (4)

- x^{2} + 8 x + 47 = 0

What are the solutions to the equation -2x^2+3x-4=0 ?
The solutions to the equation -2x^2+3x-4=0 are x= 3/4-i(sqrt(23))/4 ,x= 3/4+i(sqrt(23))/4
Find the zeros of -2x^2+3x-4=0
The zeros of -2x^2+3x-4=0 are x= 3/4-i(sqrt(23))/4 ,x= 3/4+i(sqrt(23))/4