What are the solutions to the equation x^2+20x+10=0 ?

The solutions to the equation x^2+20x+10=0 are x=-10+3sqrt(10),x=-10-3sqrt(10)

Find the zeros of x^2+20x+10=0

The zeros of x^2+20x+10=0 are x=-10+3sqrt(10),x=-10-3sqrt(10)

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x^{2} + 20 x + 10 = 0

x = - 10 + 310, x = - 10 - 310

Decimal Notation

x = - 0.51316 \dots, x = - 19.48683 \dots

Solution steps

x^{2} + 20 x + 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 20 \pm 2 0 ^{2} - 4 \cdot 1 \cdot 10}{2 \cdot 1}

2 0^{2} - 4 \cdot 1 \cdot 10 = 610

x_{1, 2} = \frac{- 20 \pm 6 10}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 20 + 6 10}{2 \cdot 1}, x_{2} = \frac{- 20 - 6 10}{2 \cdot 1}

x = \frac{- 20 + 6 10}{2 \cdot 1} : - 10 + 310

x = \frac{- 20 - 6 10}{2 \cdot 1} : - 10 - 310

The solutions to the quadratic equation are:

x = - 10 + 310, x = - 10 - 310

192 = (2 x + 12) (2 x + 8)

- 2 x^{2} + 11 x - 14 = 0

(2 x + 3) (x - 2) = 5 (x - 2)

9 x^{2} - 12 x + 1 = 0

p^{2} - 5 p - 6 = 0

What are the solutions to the equation x^2+20x+10=0 ?
The solutions to the equation x^2+20x+10=0 are x=-10+3sqrt(10),x=-10-3sqrt(10)
Find the zeros of x^2+20x+10=0
The zeros of x^2+20x+10=0 are x=-10+3sqrt(10),x=-10-3sqrt(10)