What are the solutions to the equation (2x-3)^2-1=0 ?

The solutions to the equation (2x-3)^2-1=0 are x=2,x=1

Find the zeros of (2x-3)^2-1=0

The zeros of (2x-3)^2-1=0 are x=2,x=1

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(2 x - 3)^{2} - 1 = 0

x = 2, x = 1

Solution steps

(2 x - 3)^{2} - 1 = 0

Move

1

to the right side

(2 x - 3)^{2} = 1

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

2 x - 3 = 1 : x = 2

Solve

2 x - 3 = - 1 : x = 1

The solutions to the quadratic equation are:

x = 2, x = 1

x^{2} - 16 x + 145 = 0

x^{2} - 3 x + \frac{9}{4} = 6

1 2^{2} + 8^{2} = c^{2}

3 x^{2} - 12 x + 7

3 x^{2} - 12 x + 8

What are the solutions to the equation (2x-3)^2-1=0 ?
The solutions to the equation (2x-3)^2-1=0 are x=2,x=1
Find the zeros of (2x-3)^2-1=0
The zeros of (2x-3)^2-1=0 are x=2,x=1