What are the solutions to the equation x^2-16x+145=0 ?

The solutions to the equation x^2-16x+145=0 are x=8+9i,x=8-9i

Find the zeros of x^2-16x+145=0

The zeros of x^2-16x+145=0 are x=8+9i,x=8-9i

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x^{2} - 16 x + 145 = 0

x = 8 + 9 i, x = 8 - 9 i

Solution steps

x^{2} - 16 x + 145 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 16 ) \pm ( - 16 ) ^{2} - 4 \cdot 1 \cdot 145}{2 \cdot 1}

Simplify

(- 16)^{2} - 4 \cdot 1 \cdot 145 : 18 i

x_{1, 2} = \frac{- ( - 16 ) \pm 18 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 16 ) + 18 i}{2 \cdot 1}, x_{2} = \frac{- ( - 16 ) - 18 i}{2 \cdot 1}

x = \frac{- ( - 16 ) + 18 i}{2 \cdot 1} : 8 + 9 i

x = \frac{- ( - 16 ) - 18 i}{2 \cdot 1} : 8 - 9 i

The solutions to the quadratic equation are:

x = 8 + 9 i, x = 8 - 9 i

x^{2} - 3 x + \frac{9}{4} = 6

1 2^{2} + 8^{2} = c^{2}

3 x^{2} - 12 x + 7

3 x^{2} - 12 x + 8

- 2 x^{2} + 5 x + 10 = 0

What are the solutions to the equation x^2-16x+145=0 ?
The solutions to the equation x^2-16x+145=0 are x=8+9i,x=8-9i
Find the zeros of x^2-16x+145=0
The zeros of x^2-16x+145=0 are x=8+9i,x=8-9i