What are the solutions to the equation 4(x+2)^2+6=70 ?

The solutions to the equation 4(x+2)^2+6=70 are x=2,x=-6

Find the zeros of 4(x+2)^2+6=70

The zeros of 4(x+2)^2+6=70 are x=2,x=-6

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

4 (x + 2)^{2} + 6 = 70

x = 2, x = - 6

Solution steps

4 (x + 2)^{2} + 6 = 70

Move

6

to the right side

4 (x + 2)^{2} = 64

Divide both sides by

4

(x + 2)^{2} = 16

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 2 = 16 : x = 2

Solve

x + 2 = - 16 : x = - 6

The solutions to the quadratic equation are:

x = 2, x = - 6

- 2 x + 4 (2 x + x^{2}) = - 1

x^{2} - 12 x + 17 = 0

d^{2} - 10 d + 25 = 0

0 = 2 x^{2} - 4 x - 1

9 x^{2} + 36 x + 72 = 0

What are the solutions to the equation 4(x+2)^2+6=70 ?
The solutions to the equation 4(x+2)^2+6=70 are x=2,x=-6
Find the zeros of 4(x+2)^2+6=70
The zeros of 4(x+2)^2+6=70 are x=2,x=-6