What are the solutions to the equation 5d^2+6d=-25 ?

The solutions to the equation 5d^2+6d=-25 are d=-3/5+i(2sqrt(29))/5 ,d=-3/5-i(2sqrt(29))/5

Find the zeros of 5d^2+6d=-25

The zeros of 5d^2+6d=-25 are d=-3/5+i(2sqrt(29))/5 ,d=-3/5-i(2sqrt(29))/5

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5 d^{2} + 6 d = - 25

d = - \frac{3}{5} + i \frac{2 29}{5}, d = - \frac{3}{5} - i \frac{2 29}{5}

Solution steps

5 d^{2} + 6 d = - 25

Move

25

to the left side

5 d^{2} + 6 d + 25 = 0

Solve with the quadratic formula

d_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 5 \cdot 25}{2 \cdot 5}

Simplify

6^{2} - 4 \cdot 5 \cdot 25 : 429 i

d_{1, 2} = \frac{- 6 \pm 4 29 i}{2 \cdot 5}

Separate the solutions

d_{1} = \frac{- 6 + 4 29 i}{2 \cdot 5}, d_{2} = \frac{- 6 - 4 29 i}{2 \cdot 5}

d = \frac{- 6 + 4 29 i}{2 \cdot 5} : - \frac{3}{5} + i \frac{2 29}{5}

d = \frac{- 6 - 4 29 i}{2 \cdot 5} : - \frac{3}{5} - i \frac{2 29}{5}

The solutions to the quadratic equation are:

d = - \frac{3}{5} + i \frac{2 29}{5}, d = - \frac{3}{5} - i \frac{2 29}{5}

p^{2} - 8 p + 21 = 6

6 x^{2} + 48 = 0

x^{2} - 2 x^{2} = 0

9 x^{2} + 12 x = - 4

2 x^{2} + 4 x + 0 = 0

What are the solutions to the equation 5d^2+6d=-25 ?
The solutions to the equation 5d^2+6d=-25 are d=-3/5+i(2sqrt(29))/5 ,d=-3/5-i(2sqrt(29))/5
Find the zeros of 5d^2+6d=-25
The zeros of 5d^2+6d=-25 are d=-3/5+i(2sqrt(29))/5 ,d=-3/5-i(2sqrt(29))/5