What are the solutions to the equation (c-1)^2+7=3 ?

The solutions to the equation (c-1)^2+7=3 are c=2i+1,c=-2i+1

Find the zeros of (c-1)^2+7=3

The zeros of (c-1)^2+7=3 are c=2i+1,c=-2i+1

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(c - 1)^{2} + 7 = 3

c = 2 i + 1, c = - 2 i + 1

Solution steps

(c - 1)^{2} + 7 = 3

Move

7

to the right side

(c - 1)^{2} = - 4

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

c - 1 = - 4 : c = 2 i + 1

Solve

c - 1 = - - 4 : c = - 2 i + 1

The solutions to the quadratic equation are:

c = 2 i + 1, c = - 2 i + 1

3 x^{2} = 7 + 5 x

x^{2} - x - 17 = 3

x, z = 3 x^{2} + x y - 2 y^{2}

x, x^{2} + y^{2} + 2 x - 3 y + 6 = 0

(x + 5) (x + 2) + 2 = 0

What are the solutions to the equation (c-1)^2+7=3 ?
The solutions to the equation (c-1)^2+7=3 are c=2i+1,c=-2i+1
Find the zeros of (c-1)^2+7=3
The zeros of (c-1)^2+7=3 are c=2i+1,c=-2i+1