What are the solutions to the equation 4x^2-7x-1=0 ?

The solutions to the equation 4x^2-7x-1=0 are x=(7+sqrt(65))/8 ,x=(7-sqrt(65))/8

Find the zeros of 4x^2-7x-1=0

The zeros of 4x^2-7x-1=0 are x=(7+sqrt(65))/8 ,x=(7-sqrt(65))/8

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4 x^{2} - 7 x - 1 = 0

x = \frac{7 + 65}{8}, x = \frac{7 - 65}{8}

Decimal Notation

x = 1.88278 \dots, x = - 0.13278 \dots

Solution steps

4 x^{2} - 7 x - 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 4 ( - 1 )}{2 \cdot 4}

(- 7)^{2} - 4 \cdot 4 (- 1) = 65

x_{1, 2} = \frac{- ( - 7 ) \pm 65}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 7 ) + 65}{2 \cdot 4}, x_{2} = \frac{- ( - 7 ) - 65}{2 \cdot 4}

x = \frac{- ( - 7 ) + 65}{2 \cdot 4} : \frac{7 + 65}{8}

x = \frac{- ( - 7 ) - 65}{2 \cdot 4} : \frac{7 - 65}{8}

The solutions to the quadratic equation are:

x = \frac{7 + 65}{8}, x = \frac{7 - 65}{8}

2 x^{2} - 27 x + 12 = - 10 x - 19

x, x^{2} + y^{2} + 8 x - 6 y + 30 = 0

(2 x + 4) (2 x - 4) = (x - 8) (x + 3) + 6

3 x^{2} - 1 x - 4 = 0

3 x^{2} - 6 x + 24 = 0

What are the solutions to the equation 4x^2-7x-1=0 ?
The solutions to the equation 4x^2-7x-1=0 are x=(7+sqrt(65))/8 ,x=(7-sqrt(65))/8
Find the zeros of 4x^2-7x-1=0
The zeros of 4x^2-7x-1=0 are x=(7+sqrt(65))/8 ,x=(7-sqrt(65))/8