What are the solutions to the equation x^2+(x+5)^2+83=1200 ?

The solutions to the equation x^2+(x+5)^2+83=1200 are x=21,x=-26

Find the zeros of x^2+(x+5)^2+83=1200

The zeros of x^2+(x+5)^2+83=1200 are x=21,x=-26

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x^{2} + (x + 5)^{2} + 83 = 1200

x = 21, x = - 26

Solution steps

x^{2} + (x + 5)^{2} + 83 = 1200

Expand

x^{2} + (x + 5)^{2} + 83 : 2 x^{2} + 10 x + 108

2 x^{2} + 10 x + 108 = 1200

Move

1200

to the left side

2 x^{2} + 10 x - 1092 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 2 ( - 1092 )}{2 \cdot 2}

1 0^{2} - 4 \cdot 2 (- 1092) = 94

x_{1, 2} = \frac{- 10 \pm 94}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 10 + 94}{2 \cdot 2}, x_{2} = \frac{- 10 - 94}{2 \cdot 2}

x = \frac{- 10 + 94}{2 \cdot 2} : 21

x = \frac{- 10 - 94}{2 \cdot 2} : - 26

The solutions to the quadratic equation are:

x = 21, x = - 26

x^{2} + 35 = - 12 x

t^{2} + 6 t + 5 = 0

z^{2} - 6 z

z^{2} + 8 z

z^{2} + 2 z

What are the solutions to the equation x^2+(x+5)^2+83=1200 ?
The solutions to the equation x^2+(x+5)^2+83=1200 are x=21,x=-26
Find the zeros of x^2+(x+5)^2+83=1200
The zeros of x^2+(x+5)^2+83=1200 are x=21,x=-26