What are the solutions to the equation 4x^2-14x+7=4-x ?

The solutions to the equation 4x^2-14x+7=4-x are x=3,x= 1/4

Find the zeros of 4x^2-14x+7=4-x

The zeros of 4x^2-14x+7=4-x are x=3,x= 1/4

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4 x^{2} - 14 x + 7 = 4 - x

x = 3, x = \frac{1}{4}

Decimal Notation

x = 3, x = 0.25

Solution steps

4 x^{2} - 14 x + 7 = 4 - x

Move

x

to the left side

4 x^{2} - 13 x + 7 = 4

Move

4

to the left side

4 x^{2} - 13 x + 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 13 ) \pm ( - 13 ) ^{2} - 4 \cdot 4 \cdot 3}{2 \cdot 4}

(- 13)^{2} - 4 \cdot 4 \cdot 3 = 11

x_{1, 2} = \frac{- ( - 13 ) \pm 11}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 13 ) + 11}{2 \cdot 4}, x_{2} = \frac{- ( - 13 ) - 11}{2 \cdot 4}

x = \frac{- ( - 13 ) + 11}{2 \cdot 4} : 3

x = \frac{- ( - 13 ) - 11}{2 \cdot 4} : \frac{1}{4}

The solutions to the quadratic equation are:

x = 3, x = \frac{1}{4}

5 x^{2} - 40 x - 97 = 3

- 3 x^{2} + 8 x - 5 = 0

4 z + z^{2} + 12 = 0

1 - x (- 5) - (- 5) + x^{2} = 0

(3 x + 4)^{2} = 24 x + 16

What are the solutions to the equation 4x^2-14x+7=4-x ?
The solutions to the equation 4x^2-14x+7=4-x are x=3,x= 1/4
Find the zeros of 4x^2-14x+7=4-x
The zeros of 4x^2-14x+7=4-x are x=3,x= 1/4